4x^2-57x+170=0

Solution for 4x^2-57x+170=0 equation:

4x^2-57x+170=0

a = 4; b = -57; c = +170;
Δ = b2-4ac
Δ = -572-4·4·170
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-23}{2*4}=\frac{34}{8}
=4+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+23}{2*4}=\frac{80}{8}
=10
$